Question 1
Investigators evaluated the effect of education (E1=1 if college or more, E2=1 ifMasters degree or more, E1=E2=0 if less than college), Mother’s Education (M=1 ifcollege or more, 0 otherwise), and age (A, continuous, in years) on employmentstatus (yes/no) using the following Logistic regression model:
Logit= a + B1*E1+B2*E2 + B3*A + B4*M + B5*A*M
SAS was used to create the following estimates:
a= -2, B1=0.2, B2=0.4, B3=0.1, B4=0.3, B5=0.02.
Calculate the odds that a 25 year old with just a college degree whose mother had acollege degree is employed. Enter the odds to three decimal places.
0.1
pts
Question 2
For the 25 year old above, with just a college degree whose mother had a collegedegree, calculate the probability of being employed. Enter the probability to threedecimal places.

11/16/22, 9:06 AM Quiz: Assessment #10
https://rutgers.instructure.com/courses/207144/quizzes/655486/take 2/4
0.1
pts
Question 3
In the example from question 1, calculate the odds of having a job for someone with acollege degree versus less than college after adjusting for age and maternaleducation. Calculate to 3
places beyond the decimal point.
0.1
pts
Question 4
For someone who is 25 years old and adjusting for education, calculate the odds ratioof being employed for someone whose mother had a college degree versus a motherwho had a high school degree. Calculate the odds ratio to 3 places beyond thedecimal point.
0.1
pts
Question 5
For someone who is 35 years old and adjusting for education, calculate the odds ratioof being employed for someone whose mother had a college degree versus a motherwho had a high school degree. Calculate the odds ratio to 3 places beyond thedecimal point.

11/16/22, 9:06 AM Quiz: Assessment #10
https://rutgers.instructure.com/courses/207144/quizzes/655486/take 3/4
0.1
pts
Question 6
For 35 year olds who have mothers has a high school education, calculate the oddsof employment for those with a master’s degree versus the odds of employment forthose with a college degree. Calculate the odds ratio to 3 places beyond the decimalpoint.
0.1
pts
Question 7
For those who are college educated and have a mother that is college educated, theodds of employment increase by what percent with an increase of ten years in age? Enter the answer to two places beyond the decimal place.
0.1
pts
Question 8
True
False
The Akaike Information Criterion in relation to -2 times the log-likelihood is similar tothe adjusted r-square in relation to the r-square value in that it adjusts for the numberof parameters to be estimated in the model.
0.1
pts
Question 9

11/16/22, 9:06 AM Quiz: Assessment #10
https://rutgers.instructure.com/courses/207144/quizzes/655486/take 4/4
Quiz saved at 9:06am
substantially greater than
relatively equal to
substantially different than
substantially less than
When comparing models for the response that include different sets of covariates, wewould choose the model with the set of covariates that gives an AIC that is_________________ the AIC’s of the other models.
0.1
pts
Question 10
Examine whether the Akaike Information Criterion decreases
See if the significance level of the parameter of interest changes when the confounder isadded to the model
Examine whether the parameter of interest changes by more than 10% when adding theconfounder
Test whether the the potential confounder is significant at the 0.20 alpha level

Which of the following is not a use of security market indicator series? Select one.

Question 4 options:

Question 5 (2 points)

A properly selected sample for use in constructing a market indicator series will consider the sample’s source, size, and which other factor? Select one.

Question 5 options:

Question 6 (2 points)

It is essential in an investment policy statement that both the client and the portfolio manager agree on an appropriate benchmark portfolio.

Question 6 options:

Question 7 (2 points)

The Standard & Poor’s 500 index is an example of a value-weighted index.

Question 7 options:

Question 8 (2 points)

The most common way to test a portfolio manager’s performance is to compare the portfolio return to a benchmark.

Question 8 options:

Question 9 (2 points)

The general purpose of a market indicator series is to provide an overall indication of aggregate market changes or movements.

Question 9 options:

Question 10 (2 points)

A bond market index is easier to create than a stock market index because the universe of bonds is much broader than that of stocks.

Question 10 options:

Basis: Long hedge: Effective purchase price = S2 – (F2 – F1) = F1 + (S2 – F2) = F1 + b2
Short hedge: Effective selling price = S2 + (F1 – F2) = F1 + (S2 – F2) = F1 + b2
Optimal hedge ratio:


F
S h =
Optimal number of contracts:
A
F
V
N h
V
=
Optimal number of contracts using β:
P
N
F
= 
CAPM:
( ) ( ) E r r r r = + − f m f 
Forward/futures price: F0
▪ No income: F0 = S0 e
r T
▪ Known dollar income: F0 = (S0 – I0) e
r T
▪ Known yield income: F0 = S0 e
(r – q) T
o Index: F0 = S0 e
(r – q) T
o Currency: F0 = S0 e
(r – rf)T
o Investment commodity:F0 = S0 e
(r + u) T or F0 = (S0 + U0) e
r T
Cost of carry (investment): F0 = S0 e c T
where c = r, r-q, r-rf , r+u
▪ Consumption commodity: F0 ≤ S0e
(r + u) T or F0 ≤ (S0 + U0) e
r T
Convenience yield: F0 = S0 e
(r+u – y) T or F0 = (S0 + U0) e
(r-y) T
Value of a long forward contract: ft = (Ft – F0) e
-r (T-t)
Conversion from continuous to m compounding: Rm = m(e
Rc/m
– 1)
Conversion from m to continuous compounding: Rc = m ln(1 + Rm/m)
Fixed side (swap):

=
−
= +
−
n
i
rt
B Le ke
i
r t
fix
i
n n
1
Floating side (swap):
B Le k e
r t
r t
fl
= + 
− −
1 1
1 1
Options
European option payoff: Long call = max (ST – K, 0)
Short call = –max (ST – K, 0) or min (K – ST, 0)
Long put = max (K – ST, 0)
Short put = –max (K – ST, 0) or min (ST – K, 0)
Long asset = ST – S0
Short asset = S0 – ST
European option bounds: Upper (no dividends): c ≤ S0 Lower (no div/s): c ≥ S0 – Ke
-rT
p ≤ Ke
-rT p ≥ Ke
-rT – S0
Upper (dividends): c ≤ S0 – D Lower (div/s): c ≥ (S0 – D) – Ke
-rT

p ≤ Ke
-rT
p ≥ Ke
-rT – S0 + D
Upper (yield): c ≤ S0e
-qT
Lower (yield): c ≥ S0e
-qT – Ke
-rT

p ≤ Ke
-rT
p ≥ Ke
-rT – S0e
-qT
Upper (currency): c ≤ S0e
-rfT
Lower (currency): c ≥ S0e
-rfT – Ke
-rT

p ≤ Ke
-rT
p ≥ Ke
-rT – S0e
-rfT
Upper (futures): c ≤ F0 e
-rT
Lower (futures): c ≥ (F0 – K)e
-rT

p ≤ Ke
-rT
p ≥ (K – F0)e
-rT
Put-call parity: European options: No dividends: c + Ke
-rT = p + S0
Dividends: c + Ke
-rT = p + (S0 – D)
Yield: c + Ke
-rT = p + S0e
-qT
Currency: c + Ke
-rT = p + S0e
-rfT
Futures: c + Ke
-rT = p + F0e
-rT
American: No dividends: C + Ke
-rT ≤ P + S0
Binomial Trees
Up and down parameters related to volatility:
,
t t u e d e    − 
= =
Single-step delta: No income:
0
( )
f f u d
S u d
−
 =
−
Yield
0 ( )
u d
q t
f f
u d e S

−
 =
−
Risk-neutral probability: No income:
r t d
p
u d
e

−
=
−
Yield:
( ) r q t d
p
u d
e
− 
−
=
−
Futures:
u d
d
p
−
−
=
1
Discounted expected payoff: f = e
–r t
[pfu + (1 – p)fd]
Black-Scholes option pricing
Lognormal distribution:
2
0
ln ln μ ,
2
S S T
 T T 
   
  + −            
European (no dividends): c = S0 N(d1) – Ke
-rT N(d2)
p = Ke
-rT N(–d2) – S0 N(–d1)
2
0
1
ln( / ) ( / 2) S K r T d
T


+ +
=
d 2 = d1− T
European (yield): c = S0e
-qTN(d1) – Ke
-rT N(d2)
p = Ke
-rT N(–d2) – S0e
-qTN(–d1)
2
0
1
ln( / ) ( / 2) S K r q T d
T


+ − +
=
European (currency): c = S0e
-rfTN(d1) – Ke
-rT N(d2)
p = Ke
-rT N(–d2) – S0e
-rfTN(–d1)
2
0
1
ln( / ) ( / 2) S K r rf T d
T


+ − +
=
European (futures): c = e
-rT[F0N(d1) – KN(d2)]
p = e
-rT [KN(–d2) – F0N(–d1)]

2
0
1
ln( / ) / 2 F K T d
T


+
=
Greek values
/ 2
2
2π
1
( )
x N x e
−

=
Delta: ΔCALL = N(d1), ΔPUT = N(d1) – 1 with
2
0
1
ln( / ) ( / 2) S K r T d
T


+ +
= ,
ΔCALL = e-qT N(d1), ΔPUT = e-qT (N(d1)-1) with
2
0
1
ln( / ) ( / 2) S K r q T d
T


+ − +
=
Gamma:
S T
N d
0
( 1)
 = , or
0
( )1
qT N d e
S T 
−

 =
Vega:
 = S0 TN(d1), or 0 ( )1
qT  S T N d e− =

Hedging with futures versus hedging with spot: HF = e –rT HA, HF = e –(r-q)T HA
Table for N(x) when x ≤ 0
This table shows values for N(x) for x ≤ 0. The table should be used with interpolation. For example:
N(-0.1234)= N(-0.12) -0.34[N(-0.12)-N(-0.13)]
= 0.4522-0.34*(0.4522-0.4483)
=0.4509
x 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09
0.0 0.5000 0.4960 0.4920 0.4880 0.4840 0.4801 0.4761 0.4721 0.4681 0.4641
-0.1 0.4602 0.4562 0.4522 0.4483 0.4443 0.4404 0.4364 0.4325 0.4286 0.4247
-0.2 0.4207 0.4168 0.4129 0.4090 0.4052 0.4013 0.3974 0.3936 0.3897 0.3859
-0.3 0.3821 0.3783 0.3745 0.3707 0.3669 0.3632 0.3594 0.3557 0.3520 0.3483
-0.4 0.3446 0.3409 0.3372 0.3336 0.3300 0.3264 0.3228 0.3192 0.3156 0.3121
-0.5 0.3085 0.3050 0.3015 0.2981 0.2946 0.2912 0.2877 0.2843 0.2810 0.2776
-0.6 0.2743 0.2709 0.2676 0.2643 0.2611 0.2578 0.2546 0.2514 0.2483 0.2451
-0.7 0.2420 0.2389 0.2358 0.2327 0.2296 0.2266 0.2236 0.2206 0.2177 0.2148
-0.8 0.2119 0.2090 0.2061 0.2033 0.2005 0.1977 0.1949 0.1922 0.1894 0.1867
-0.9 0.1841 0.1814 0.1788 0.1762 0.1736 0.1711 0.1685 0.1660 0.1635 0.1611
-1.0 0.1587 0.1562 0.1539 0.1515 0.1492 0.1469 0.1446 0.1423 0.1401 0.1379
-1.1 0.1357 0.1335 0.1314 0.1292 0.1271 0.1251 0.1230 0.1210 0.1190 0.1170
-1.2 0.1151 0.1131 0.1112 0.1093 0.1075 0.1056 0.1038 0.1020 0.1003 0.0985
-1.3 0.0968 0.0951 0.0934 0.0918 0.0901 0.0885 0.0869 0.0853 0.0838 0.0823
-1.4 0.0808 0.0793 0.0778 0.0764 0.0749 0.0735 0.0721 0.0708 0.0694 0.0681
-1.5 0.0668 0.0655 0.0643 0.0630 0.0618 0.0606 0.0594 0.0582 0.0571 0.0559
-1.6 0.0548 0.0537 0.0526 0.0516 0.0505 0.0495 0.0485 0.0475 0.0465 0.0455
-1.7 0.0446 0.0436 0.0427 0.0418 0.0409 0.0401 0.0392 0.0384 0.0375 0.0367
-1.8 0.0359 0.0351 0.0344 0.0336 0.0329 0.0322 0.0314 0.0307 0.0301 0.0294
-1.9 0.0287 0.0281 0.0274 0.0268 0.0262 0.0256 0.0250 0.0244 0.0239 0.0233
-2.0 0.0228 0.0222 0.0217 0.0212 0.0207 0.0202 0.0197 0.0192 0.0188 0.0183
-2.1 0.0179 0.0174 0.0170 0.0166 0.0162 0.0158 0.0154 0.0150 0.0146 0.0143
-2.2 0.0139 0.0136 0.0132 0.0129 0.0125 0.0122 0.0119 0.0116 0.0113 0.0110
-2.3 0.0107 0.0104 0.0102 0.0099 0.0096 0.0094 0.0091 0.0089 0.0087 0.0084
-2.4 0.0082 0.0080 0.0078 0.0075 0.0073 0.0071 0.0069 0.0068 0.0066 0.0064
-2.5 0.0062 0.0060 0.0059 0.0057 0.0055 0.0054 0.0052 0.0051 0.0049 0.0048
-2.6 0.0047 0.0045 0.0044 0.0043 0.0041 0.0040 0.0039 0.0038 0.0037 0.0036
-2.7 0.0035 0.0034 0.0033 0.0032 0.0031 0.0030 0.0029 0.0028 0.0027 0.0026
-2.8 0.0026 0.0025 0.0024 0.0023 0.0023 0.0022 0.0021 0.0021 0.0020 0.0019
-2.9 0.0019 0.0018 0.0018 0.0017 0.0016 0.0016 0.0015 0.0015 0.0014 0.0014
-3.0 0.0013 0.0013 0.0013 0.0012 0.0012 0.0011 0.0011 0.0011 0.0010 0.0010
-3.1 0.0010 0.0009 0.0009 0.0009 0.0008 0.0008 0.0008 0.0008 0.0007 0.0007
-3.2 0.0007 0.0007 0.0006 0.0006 0.0006 0.0006 0.0006 0.0005 0.0005 0.0005
-3.3 0.0005 0.0005 0.0005 0.0004 0.0004 0.0004 0.0004 0.0004 0.0004 0.0003
-3.4 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0002
-3.5 0.0002 0.0002 0.0002 0.0002 0.0002 0.0002 0.0002 0.0002 0.0002 0.0002
-3.6 0.0002 0.0002 0.0001 0.0001 0.0001 0.0001 0.0001 0.0001 0.0001 0.0001
-3.7 0.0001 0.0001 0.0001 0.0001 0.0001 0.0001 0.0001 0.0001 0.0001 0.0001
-3.8 0.0001 0.0001 0.0001 0.0001 0.0001 0.0001 0.0001 0.0001 0.0001 0.0001
-3.9 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
-4.0 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
Table for N(x) when x ≥ 0
This table shows values for N(x) for x ≥ 0. The table should be used with interpolation. For example:
N(0.6278)= N(0.62) + 0.78[N(0.63)-N(0.62)]
= 0.7324+0.78*(0.7357-0.7324)
=0.7350
x 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09
0.0 0.5000 0.5040 0.5080 0.5120 0.5160 0.5199 0.5239 0.5279 0.5319 0.5359
0.1 0.5398 0.5438 0.5478 0.5517 0.5557 0.5596 0.5636 0.5675 0.5714 0.5753
0.2 0.5793 0.5832 0.5871 0.5910 0.5948 0.5987 0.6026 0.6064 0.6103 0.6141
0.3 0.6179 0.6217 0.6255 0.6293 0.6331 0.6368 0.6406 0.6443 0.6480 0.6517
0.4 0.6554 0.6591 0.6628 0.6664 0.6700 0.6736 0.6772 0.6808 0.6844 0.6879
0.5 0.6915 0.6950 0.6985 0.7019 0.7054 0.7088 0.7123 0.7157 0.7190 0.7224
0.6 0.7257 0.7291 0.7324 0.7357 0.7389 0.7422 0.7454 0.7486 0.7517 0.7549
0.7 0.7580 0.7611 0.7642 0.7673 0.7704 0.7734 0.7764 0.7794 0.7823 0.7852
0.8 0.7881 0.7910 0.7939 0.7967 0.7995 0.8023 0.8051 0.8078 0.8106 0.8133
0.9 0.8159 0.8186 0.8212 0.8238 0.8264 0.8289 0.8315 0.8340 0.8365 0.8389
1.0 0.8413 0.8438 0.8461 0.8485 0.8508 0.8531 0.8554 0.8577 0.8599 0.8621
1.1 0.8643 0.8665 0.8686 0.8708 0.8729 0.8749 0.8770 0.8790 0.8810 0.8830
1.2 0.8849 0.8869 0.8888 0.8907 0.8925 0.8944 0.8962 0.8980 0.8997 0.9015
1.3 0.9032 0.9049 0.9066 0.9082 0.9099 0.9115 0.9131 0.9147 0.9162 0.9177
1.4 0.9192 0.9207 0.9222 0.9236 0.9251 0.9265 0.9279 0.9292 0.9306 0.9319
1.5 0.9332 0.9345 0.9357 0.9370 0.9382 0.9394 0.9406 0.9418 0.9429 0.9441
1.6 0.9452 0.9463 0.9474 0.9484 0.9495 0.9505 0.9515 0.9525 0.9535 0.9545
1.7 0.9554 0.9564 0.9573 0.9582 0.9591 0.9599 0.9608 0.9616 0.9625 0.9633
1.8 0.9641 0.9649 0.9656 0.9664 0.9671 0.9678 0.9686 0.9693 0.9699 0.9706
1.9 0.9713 0.9719 0.9726 0.9732 0.9738 0.9744 0.9750 0.9756 0.9761 0.9767
2.0 0.9772 0.9778 0.9783 0.9788 0.9793 0.9798 0.9803 0.9808 0.9812 0.9817
2.1 0.9821 0.9826 0.9830 0.9834 0.9838 0.9842 0.9846 0.9850 0.9854 0.9857
2.2 0.9861 0.9864 0.9868 0.9871 0.9875 0.9878 0.9881 0.9884 0.9887 0.9890
2.3 0.9893 0.9896 0.9898 0.9901 0.9904 0.9906 0.9909 0.9911 0.9913 0.9916
2.4 0.9918 0.9920 0.9922 0.9925 0.9927 0.9929 0.9931 0.9932 0.9934 0.9936
2.5 0.9938 0.9940 0.9941 0.9943 0.9945 0.9946 0.9948 0.9949 0.9951 0.9952
2.6 0.9953 0.9955 0.9956 0.9957 0.9959 0.9960 0.9961 0.9962 0.9963 0.9964
2.7 0.9965 0.9966 0.9967 0.9968 0.9969 0.9970 0.9971 0.9972 0.9973 0.9974
2.8 0.9974 0.9975 0.9976 0.9977 0.9977 0.9978 0.9979 0.9979 0.9980 0.9981
2.9 0.9981 0.9982 0.9982 0.9983 0.9984 0.9984 0.9985 0.9985 0.9986 0.9986
3.0 0.9987 0.9987 0.9987 0.9988 0.9988 0.9989 0.9989 0.9989 0.9990 0.9990
3.1 0.9990 0.9991 0.9991 0.9991 0.9992 0.9992 0.9992 0.9992 0.9993 0.9993
3.2 0.9993 0.9993 0.9994 0.9994 0.9994 0.9994 0.9994 0.9995 0.9995 0.9995
3.3 0.9995 0.9995 0.9995 0.9996 0.9996 0.9996 0.9996 0.9996 0.9996 0.9997
3.4 0.9997 0.9997 0.9997 0.9997 0.9997 0.9997 0.9997 0.9997 0.9997 0.9998
3.5 0.9998 0.9998 0.9998 0.9998 0.9998 0.9998 0.9998 0.9998 0.9998 0.9998
3.6 0.9998 0.9998 0.9999 0.9999 0.9999 0.9999 0.9999 0.9999 0.9999 0.9999
3.7 0.9999 0.9999 0.9999 0.9999 0.9999 0.9999 0.9999 0.9999 0.9999 0.9999
3.8 0.9999 0.9999 0.9999 0.9999 0.9999 0.9999 0.9999 0.9999 0.9999 0.9999
3.9 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000
4.0 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000 1.0000

WRITING CODE

When you are asked to write a program in the questions below, you should write one Rust source code file that lives in the code/plain/src/bin/ directory, has a mainfunction, and can be run with cargo run --bin foo (where foo.rs is the name of the Rust source code file). Do not use any additional crates in your solutions.

QUESTION: DATA LAYOUT

1. Write one program examlayout1.rs that, for each of the following types, creates a value of that type and then prints it:
   • Vec<String>
   • &[u8]
   • Box<u8>
   • Box<&u8>
   • Box<[u8]>
   • Box<&[u8]>
   • Box<Box<u8>>
   • Box<[u8; 4]>
   • [Box<u8>; 4]
   • [Option<u8>; 4]
   • Vec<[u8; 4]>

   Use Debug formating with {:?}) to print each value. Your program must have a main function.

2. For each of the following types, draw a diagram to illustrate the data layout in memory when a local variable x contains a value of that type.
   • &[u8]
   • Box<u8>
   • Box<&u8>
   • Vec<[u8; 4]>

   You can draw your answers on paper, take photos, and include them in your PDF.

3. Write one program examlayout2.rs that, for each of the following types, creates a value of that type and then prints out all of the memory addresses used to store the value. In particular, your program should print out the memory addresses used on the stack and on the heap. You must print out the memory addresses, and you can print out the contents of those memory addresses if you like.
   • Box<u8>
   • Vec<String>

I need assistance with solving this question.

Consider the following information for a given policy :

a. δ = 0. 03

b. Level premium ? = $3500

c. No expenses.

d. µ = 0. 0007

e. Benefit payment ? = $150, 000

(i) Using Thiele’s Differential Equation, solve analytically (using

calculus) for the policy value ???.

(ii) Find the unique solution to this differential equation clearly

showing why this is the case.

(iii) Describe the what happens to the policy value as ? → ∞.

Prove that if µ is constant then
?+?
?? for all
? = ??
?+?
?, ? ??? ? ≥ 0
(b) For a Whole Life Policy with death benefit of $5000, benefit
payable at the end of year of death, determine 1? given
?
µ = 0. 07 and ? = 0. 07.
(c) Consider the following information for a given policy :
a. δ = 0. 03
b. Level premium ? = $3500
c. No expenses.
d. µ = 0. 0007
e. Benefit payment ? = $150, 000
(i) Using Thiele’s Differential Equation, solve analytically (using
calculus) for the policy value ???.
(ii) Find the unique solution to this differential equation clearly
showing why this is the case.
(iii) Describe the what happens to the policy value as ? → ∞.
(d) Consider the following policy basis for a 20 year term life policy
with:
Survival model: De Moivre’s Law ω = 105
Interest: ? = 0. 06
Expenses: No expenses
Sum Insured: $60,000
By using Microsoft Excel or otherwise, determine 10?? using the
numerical approximation (Euler’s Method) for the solution to
Thiele’s Differential Equation. Assume a time step of ℎ = 0. 05.
Total: 20 marks
Question 2:
Consider the following joint density function for (2) lives (x) and (y):
?(?, ?) = ?(? , ,
2
+ ?
2
) 0 < ? < 3 0 < ? < 2
(a) Calculate ?? .
??
(b) Calculate ?? .
??
(c) For a whole life policy of a joint status (following the mortality
model above) with sum insured of $250,000, benefit payable
immediately upon death, determine the net single premium.
Total: 15 marks

Q1. You have been hired as an economic consultant by a price-taking (a perfectly competitive) firm that produces T-shirts. The firm already has a factory, so it is operating in the short-run. The price of T-shirt is $9, the hourly wage is $24, and each T-shirt requires $1 worth of material. The following table shows the relationship between the number of workers and output of T-shirts.

Note: For answering question-1 (a) and (b) students are required to show all possible calculations.

Q2. See around you and pick up a firm which is either dominating the market or trying to create monopoly.

• (a) Write in brief about the firm chosen and explain how the firm is trying to create a monopoly or dominating the market? (2 points)
• (b) Elaborate your opinion, why we as a society should worry about a firm trying to create a monopoly? (2points)
• (c) Discuss some policy options a government could have to intervene in such market and prevent the monopoly creation. (2points)

1.National income accounting deals with the aggregate measure of the outcome of economic activities. The most common measure of the aggregate production in an economy is Gross Domestic Product (GDP). The table below provides Country’s national income accounting. Use this data to answer the following questions.

a.Calculate the GDP by using the Expenditure Approach Method (1Mark)

b.Calculate the GDP by using the Factor Payment Approach or the Income Approach Method. (1 Mark)

2.Suppose people consume 3 different goods. The following table shows the prices and quantities of each good consumed in 2006, 2007, and 2008.

a.Calculate nominal GDP in each of the three years. (1.5 Marks)

b.Calculate Real GDP in each of the three years, using 2006 as the base year. (1.5 Marks)

c.Calculate the rate of inflation for 2007 and 2008 using the GDP deflator as your price index. Assume that 2006 is still the base year. (2 Marks)

d.Using the quantities from 2006 for your market basket, and 2006 as your base year, calculate the CPI for 2006, 2007 and 2008. (2 Marks)

e.Using the CPI calculate the rate of inflation. (1 Mark)

A Cube of mass 8kg (All sides the same length) is placed at a depth of 2m in pure fresh water of density 1000kgm−3 and released.

Once released it starts to accelerate upwards at 0.5ms−2, what is the length of one of the sides of the cube.

Assume that the above 2022 admission data is the population is known

Use the R program and the codes given in Lectures and Discussions to answer the questions below

l.Points=1+(1+1)=3.

(a)What is the numerical value of the population size N?

(b)Calculate the population mean and the population variance using the equations (2.8) and (2.9) in Text. Copy and paste the R code and output as the answer.

ll.Points=1+(1+1)=3.

(a) Draw a simple random sample without replacement of sizen=3. Copy and paste the R code and output as the answer.

(b)Calculate the sample mean and the sample variance using the equations(2.11)and(2.13)in Text Copy and paste the R code and output as the answer

lll.Points=(1+1)+(0.5+0.5+0.5+0.5)=4.

(a)Calculate the variance and standard error of the sample mean using the equations(2.14)and(2.15 in Text.Copy and paste the R code and output as the answer

(b)Calculate the difference between the sample mean and population mean. What is the meaning of the sign of the difference? What is the interpretation of the magnitude of the difference? Express the difference in the standard error unit i.e as a constant time of the standard error and specify the numerical value of it.